Ft Lbs of Energy? Does that mean that a target would be hit with a force equal to one pound of pressure?
gun writers always compare the 222 Rem equal to almost like the 223 Rem. Now this would be based on a gun writers observation since the powder capacity is near the same but both can shoot let say the same 50 grain HP bullet.. However just say, as a fox fur friendly gun. Would the 222 Rem using like 50 Grain HP bullets be less destructive on a red fox then the same 50 grain HP bullet shot from a 223 Rem?
Looking at the Remington factory charts data for 50 Grain Hollow Point .224 bullets I notice a difference in ft lbs of Energy for the two cartridges..
Rem 223 100 yard ft lbs of Energy is 933 ft lbs The ballistic coefficients is .0192
............222 Rem has minus -162 ft lbs of Energy
Rem 222 100 yard ft lbs of Energy is 771 ft lbs The Ballistic Coefficients is .0188
So using the factory ammo for a 222 Rem the red fox would be hit with 162 ft lbs of less Energy from the same 50 grain HP bullet.
The ballistic coefficients of the 222 Rem is also .0004 less then the 223 Rem bullet. Would this mean that the 222 Rem bullet would blow up that much more then the 223 Rem bullet?
Could a red fox hunter be better off using a 222 Rem 50 grain HP factory round for fox instead of the 223 Rem 50 grain HP based on the minus - 162 ft lbs of energy difference?
Could a reloader then reduce the 223 Rem 50 grain HP bullet down to the 222 Rem factory Energy too and make it less destructive on a side shot at red fox?
Would a red fox shot at 100 yards be hit with 162 more pound of ft lb energy if the person shot it with the 223 instead of the 222? Also is that what it would equate to..Like hitting it with 162 pounds more of impact pounds?
